Since the Fourier Transform of the product of two functions is the same as the convolution of their Fourier Transforms, and the Fourier Transform is an isometry on $L^2$, all we need find is an …

Oct 7, 2015 · Convolution - Difference of two random variables with different distributions Ask Question Asked 10 years, 2 months ago Modified 3 years, 8 months ago

Sep 12, 2024 · I am merely looking for the result of the convolution of a function and a delta function. I know there is some sort of identity but I can't seem to find it. $\int_ {-\infty}^ {\infty} f …

Oct 25, 2022 · My final question is: what is the intuition behind convolution? what is its relation with the inner product? I would appreciate it if you include the examples I gave above and …

Apr 16, 2016 · You should end up with a new gaussian : take the Fourier tranform of the convolution to get the product of two new gaussians (as the Fourier transform of a gaussian is …

Convolution is something like a weighted average operation: for each point you calculate a weighted (the weight being given by the other function) average of values of some function at …

Jan 23, 2015 · Convolution of 2 uniform random variables Ask Question Asked 10 years, 10 months ago Modified 8 years, 7 months ago

Dec 14, 2024 · 0 We started recently talking in my signal processing class about the convolution integral, and in theory, it sounds easy enough but now after a few exercises I realize I either …

Sep 6, 2015 · 3 The definition of convolution is known as the integral of the product of two functions $$ (f*g) (t)\int_ {-\infty}^ {\infty} f (t -\tau)g (\tau)\,\mathrm d\tau$$ But what does the …

But in general, convolution of functions is almost a ring (there's no exact identity element). The linear space of compactly supported distributions forms an actual ring under convolution, and …